Final Test

Ecei Test

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5 Days to Go

As the days passes on the more we are press on time to complete everything for school and getting every thing out of the way for the upcoming exams. For today's class we went old school and went over the worksheet with the magnet and the coil of wire. Remember the charge of the coil at the end where the magnet enters or come out of is the opposite of what you think.

Example:








Then after we went over some questions on a different worksheet with ratios of voltage and coils. Finally for review for tomorrow's test and Monday's exam do questions 44- to the last last question on the exam review and good luck every one!

Again, no one seemed to scribe so I guess I'll do it.

Today, Ms. Kozoriz found out that for the last two days we technically didn't learn anything new, since we did Sudoku with one sub and just went over answers with another.

So, Ms. K popped in a DVD so that we could learn more about how magnetism and electricity are related, and how electricity can be converted into magnetism and vice versa.

From there, we were handed a worksheet that had to do with transformers and told to finish the worksheet that had seven questions that use the equation that deals with Electromotive Force or Voltage Potential Difference.

The potential date for the test is either Wednesday, if Ms. K believes we're ready, and if not, Thursday.

Next scribe for tomorrow will be Tony.

Friday, January 16 2009

Hello, no-one seemed to scribe for today so i guess i'll take the liberty of doing it, today in class we had a sub yet again, and we recieved so more sheets, as usual, and we then corrected Chapter 37: Electro magnetic induction and Chapter 25 Study Guide. Our Assignments/Homework for Monday is the Grade 12 physics worksheet on Electromagnetic Induction and finish the combination circuits sheet.

The answers for Chap. 25 and 37 are:
Chapter 25 Study Guide:

loop
one
current
stationary
parallel to
relative
current
magnetic

voltage
force
volt
force
direction
work
potential
induced
perpendicular to

mechanical
loops
magnetic
iron
armature
lines
voltage
increased
strength
direction
180 degrees
opposite
mechanical

energy
magnetic
60
60 Hz
current voltage
average
effective
maximum

direction
flux
current
armature
increases
back-EMF
reduces
reduces

magnetic
lines
charge
larger
slower
work
current
energy

voltage
energy
coils
core
voltage
magnetic
current
mutual
voltage
coils
less than
greater
greater
less than

Chapter 37: Electro Magnetic Induction Sheet:
1. related.
the motion of electric charges.
the motion of a magnet.
magnetic field in the loop.
electromagnetic induction.

2. doubles.
doubles.

3. electric field.
magnetic field.
electromagnetic waves.

Thusday, January 15 2009

Hello Everybody,

Kamil reporting in, sorry for being a day late, its a long story.
On thursdays class we had a substitute, he gave us sudoku puzzles for an obscure reason, and said if we finished them we might get an A+ for the whole course, yeah and legless man can sprint. After words we recieved a combined circuits work sheet and a chapter 25 fill in the blanks sheet.

A very Cold, Cold Day

Hello everyone, Rojuane here to scribe.
I almost forgot to scribe, but I remembered!

Today a good class. We basically went over the worksheets that were given a couple of days ago. The answers to the Compound Circuits are found on the blog just below my scribe. The Power in Electric Circuits worksheet with the 4 diagrams were assigned by groups to find the Current, Volt and Resistor. Then that's when the bell rang.

Here's stuff to know about a series circuit:
Current is constant throughout the entire circuit. For the individual potential drops add up to the total potential drop.

For a parallel circuit:
Individual currents add up to the total current. Potential difference is constant across all parts of the circuit.

Here are things to REMEMBER:
Test on Electric Current: Tuesday, January 20th, 2009
Physics Exam: January 26th, 2009 - AFTERNOON

Make sure to do your Physics Exam Review to do well on the exam and to refresh your memory!
Good Luck Everyone!

Last Blog! YAY! Sorry for the late blog!
Kamil, you're next.. so you better do it!
Off to bed for a very early doctor's appointment,
Goodnight! :)

Combination Circuits Worksheet

Combinationcircuits

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For today's class, we did a lab on Parallel and Series Circuit. The lab can be found on the green text book page 479. The purpose of doing this particular lab is to be able to construct series, parallel and combination circuits. After doing the lab, we were given the rest of the period to either work on the two worksheets that were given the day before or work on the exam review.
And that was everything for today.
The next scribe is ROJUANE!

For today's class, we started off by watching a movie about Electric Current. We were to write 5 to 7 points about the movie. We then went over the questions from the green book that was assigned last Friday. Here are the answers:

1. a.) 25 ohms
b.) 2 A
c.) 40 V and 10 V
d.) 80 W and 20 W

2. 2 Watts each

3. a.) 60 ohms
b.) .2 A

4. a.) 60 ohms
b.) 6 V

5. a.) 1.5 A
b.) 30 ohms

13. 6V

14. a.) 8.9 ohms
b.) 4.5 A
c.) 2.5 A

We were also given a hand out about Series and Parallel Elements. It gave us all the information to be able to calculate any individual voltages and currents. Two other worksheets were also handed out, Chapter 35: Electric Circuits and 14.8 Power in Electric Circuits to give us some practice with Series and Parallel Elements. And that was everything for today.
DONT FORGET ABOUT THE TEST ON JANUARY 20TH.

And the next scribe is...

Jan. 9, 2009 Physics

Friday's class consisted of a closer look at series and parallel circuits. Some examples of calculations include:

-Potential difference is found in the source of the circuit. Can be calculated, V = IR. In a series circuit, individual potential drops add up to the total potential drop. In a parallel circuit, it is constant across the whole circuit.

-In a series circuit, current is constant throughout the entire circuit. In parallel, individual currents are added to equal the total current.

-Resistance in a series circuit can be found by simply adding up all resistances within the circuit. However, in parallel, you must add the reciprocal of each resistor value and solve using the inverse of the total of all the resistance reciprocals.

-Power can be calculated, P = IV, in a series circuit. In parallel, it must be calculated using the formula P = V²/R.

We were also assigned questions 1-5, 13, and 14 on page 488 in the green textbook. The exam review has been handed out so start studying ;)

Christine scribes next.

Thursday's Blog

Today in class we got a lot of work sheets to go crazy over. We also did some corrected so here we go..

We went over the Chapter 23 Study Guide we got the previous day:

(Click to enlarge)

Then we got 2 new worksheets to work on: 31 Circuit Symbols and 32 Circuits and Circuit Diagrams:

(Click to enlarge)

Afterward we got another worksheet: Simple Circuits. We went over question 1:

(Click to enlarge)

Annd that's it! Question 2 on that Simple Circuits worksheet is due for tomorrow.
The next scribe will be Dana.

Wednesday's Blog

HELLOOOOOO. This is the day where Ms. K wasn't here and we had a sub.

We went over the: Resistivity Problems we got on monday with her. Here are the answers:

(click to enlarge)

After that, we got the chapter 23 study guide that was due for thursday.
That's about all we did in class that day!

Last First Day Back for Winter DMCI

Today in class we got back our test that we did before the break some did excellent and some didn't do to well... We also corrected the test as well.

The Next thing that we got were some sheet that we read with the whole class it was about Conventional Currents. We also got another sheet on Conventional Currents again.

After that we got handouts and one of the handouts will be due tomorrow. OH no on Wednesday because we only have half day tomorrow.

Study Hard and keep doing your work.
Rguy out

ps. ERiC you still are the scribe

Test Day

On thursday's class we did a test.

Happy Holidays

Eric is the next scribe

Saving the class from Eric's memory loss :P

Since "someone" forgot to blog again, I decided to blog for today. This class we went over our "Moving Charges" worksheet from question 11-16. We then went over the assigned questions from chapter 27's review worksheet. We also received a sheet with some short questions on the path of a charged particle in a magnetic field.

We can use the right hand rule to determine the path of the charged particle(positive or negative) with the following:

-For a positive charge, the palm of the hand will be pointing towards the magnetic force or away(on the paper) depending on the marking of the diagram(x is on to the page and o is away from the page). The thumb points in the direction of the moving particle and then wherever the fingers point, that is the direction the field will pull the charged particle to.

-On the other hand, if it is a negatively charged particle, the right hand rule will not apply so the negatively charged particle will be pulled in the opposite direction of the fingers.


Tomorrow is our unit test that will include everything(if Ms. K was telling the truth lol) we learned about electric and magnetic fields. Ms. K uploaded some of the derivations and equate smartboard notes for an extra study tool if anybody needs.

Richard blogs next.

Electric and Magnetic Fields Review

E B Fields Review

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Moving Charges Worksheet

Scribe for Tuesday, December 16, 2008 since Eric was kidnapped by Santa Claus and his evil green elves and hasn't scribed since.


AGENDA:

* Corrected Moving Charges Worksheet #1-10
* Read Magnetic Formulae handout
* Chapter 27 Review #1-7 for homework

The Moving Charges Worksheet was difficult to do at first, which is why Ms.K suggested on doing the questions in reverse order. Then it’s just a matter of knowing how to use your formulas correctly. Also, visualizing the problem (i.e. drawing a picture) helps a lot too.


MOVING CHARGES WORKSHEET

10. An electron is moving east to west at 5.0 x 10^5 m/s through a magnetic field. A force of 4.0 x 10-6 N north is acting on the electron. What is the magnitude and direction of the magnetic field?

F = Bqv
(4.0 x 10^6) = B (1.6 x 10^-19) (5.0 x 10^8)
B = 5 x 10^7 (into page)


9. What is the magnitude and direction of a magnetic force on a proton moving horizontally to the north at 8.6 x 10^4 m/s, as it enters a magnetic field of 1.2 T pointing vertically upward?

F = Bqv = (1.2 N/(c*m/s)) (1.6 x 10^19 C) (8.6 x 10^4 m/s) = 1.7 x 10^014 [right]


8. An electron experiences the greatest force by a magnetic field as it travels at 2.1 x 10^5 m/s when it is moving south. The force is 5.6 x 10^-13 N and up. Find the magnitude and direction of the magnetic field.

F = Bqv
(5.6 x 10^-13)/ [(1.6 x 10^-29) (2.1 x 10^5)] = B
B = 16.7 T [left]


7. A 10.0 m long high tension power line carries a current of 20.0 A perpendicular to the earth’s magnetic field of 5.5 x 10^-5 T. What is the magnetic force experienced by the power line?

F = BIL = (5.5 x 10^-5 T) (20.0 A) (10.0 m) = 0.011 N


6. A wire connecting a taillight to a motorcycle battery is 0.50 m long and is perpendicular to the Earth’s magnetic field. It experiences a force of 6.0 x 10^-5 N when carrying a current of 1.5 A. What is the magnitude of the Earth’s magnetic field at that location?

F = BIL
6.0 x 10^-5 N = B (1.5 A) (0.50 m)
B = 8 x 10^-5 T


5. A 15 cm length of wire carries a current of 20.0 A. It is perpendicular to a uniform magnetic field. If it experiences a magnetic force of 0.40 N, what is the magnetic field intensity?

B = F/(IL) = 0.4 N / (20.0 A x 0.15 m) = 0.13 T


4. Using the Millikan apparatus, a sphere of mass 3.2 x 10^-15 kg is held motionless. The plates produce an electric field strength of 19 600 N/C.


a) What forces are acting on the sphere?
electric force, gravitational force

b) What type of charge must be on the sphere?
positive

c) Determine the amount of charge on the sphere.
F_g = F_e
mg = Eq
q = mg/E = (3.2 x 10^-15 kg) (9.8 N/kg) / (19 600 N/C) = 1.6 x 10^-18 C

d) How many electrons does this correspond to?
(1.6 x 10^-18 C) x (1 electron)/(1.6 x 10^-19 C) = 10 electrons


3. The electric field between these charged parallel plates is 23 800 N/C. The drop’s mass is 2.4 x 10^-14 kg. What force would be experienced by the drop if it had the charge of three excess electrons?


F_e = Eq = (23 800 N/C) (3 x 1.6 x 10^-19 C) = 1.14 x 10^-14 N [up]
F_g = mg = (2.4 x 10^-14 kg) (9.8 N/kg) = 2.35 x 10^-13 N [down]
F_net = 2.35 x 10^-13 N - 1.14 x 10^-14 N = 2.24 x 10^-13 [down]


2. The plates are 5.0 cm apart and produce an electric field strength of 1200 N/C in the region between them. An electron enters the electric field at 1.00 x 10^2 m/s. With what velocity does the electron strike the positive plate? (Ignore gravity.)


F_e = qE = (-1.6 x 10^-19 C) (1200 N/C) = 1.92 x 10^-15 N
ma = qE
a = qE/m = (1.92 x 10^-15 N) / (9.11 x 10^-3 kg) = 2.11 x 10^14 m/s^2
v_f^2 = v_i^2 + 2ad
v_f = [(1.00 x 10^2 m/s)^2 + 2 (2.11 x 10^14 m/s^2) (0.05 m)]^0.5 = 4.6 x 10^6 m/s


1. This oil drop of mass 4.5 x 10^-15 kg has had two electrons removed. The electric field strength is 3.0 x 10^4 N/C.


a) What will happen to the drop?
F_g = mg = (4.5 x 10^-15 kg) (9.8 N/kg) = 4.4 x 10^-14 N
F_e = Eq = (3.0 x 10^4 N/C) (2 x 1.6 x 10^-19 C) = 9.5 x 10^-15 N
F_g > F_e, so drop will fall

b) What is the total force experienced by the drop?
F_net = 4.4 x 10^-14 N + 9.5 x 10^-15 N = 3.45 x 10^-14 N [down]

Next scribe is DANA.

4 Days to go!!!

So today was simple and straight forward.

We were given out a handout for Electric and Magnetic Current.

We learned about the direction of a Force on a Current Carrying Wire, and read further into that. We learned again about the right hand rules.

Two things we were told to explicitly remember about the motion of a charged particle in a magnetic field were:

1. The charge must be moving. A Magnetic field will not influence the motion of a charged particle at rest.

2. The velocity of the moving charge must have a component that is perpendicular to the direction of the magnetic field.

We were then told to work on the Moving Charges Worksheet. Questions 1 - 10.
A Tip from Ms.K. If you get stuck at one, start at number 10 and work backwards.

The next scribe will be Eric!

Physics?

http://www.youtube.com/watch?v=gq75-FKDlmA



http://www.youtube.com/watch?v=9D3wAA4448U&feature=related

December 12, 2008

Class today was simple and easy. Walking into class and hearing that I'm the scribe however wasn't as fun as I thought. Anyways, in class we did the following :

1. Finished reading "Grade 12 Physics: Gravitational Potential Energy."
2. Was handed an assignment called "Cathode Ray" but was handed in for marks.
3. Also was handed a sheet called "Appendix 2 - Fields."

So anyways, I'll see you soon and I won the bet against Mrs. Kozoriz that we had. How I was going to "forget" to scribe.

Lawrence can scribe for Monday